Construct a proof for the argument: P -> (Q ∧ R), ¬P -> R ∴ R
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Texts: Construct a proof for the argument: $P \to (Q \land R), \neg P \to R \therefore R$ 1 $P \to (Q \land R)$ 2 $\neg P \to R$ new line new subproof check proof start over Clear & Start a new Proof negation: $\neg$ conjunction: $\land$ disjunction: Show more…
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