(a) Consider the two complex numbers $z_1 = \text{cis}(-\frac{3}{4}\pi)$ and $z_2 = -1 + \sqrt{3}i$.
Added by Jose Ignacio V.
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First, let's convert 2 = -1 + V3i into polar form: r = sqrt((-1)^2 + (V3)^2) = 2 theta = arctan(V3/-1) = -pi/3 So, 2 = 2 cis(-pi/3) Show more…
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