Consider the function $f(x) = \frac{-x}{6x^2 + 1}$, $0 \le x \le 2$. This function has an absolute minimum value equal to:
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Step 1: To find the absolute minimum value of the function f(x) = (-x)/(6x^2 + 1) on the interval [0, 2], we first need to find the critical points by taking the derivative of the function and setting it equal to 0. Show more…
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