00:01
Hi, in the given question we have to answer four parts and three gene pairs are given.
00:06
Now a woman possessing the genotype, heterozygous for the first pair, homozygous recessive for the second and then again heterozygous for the third pair, is crossed with a male having homozygous recessive for the first pair and heterozygous for second and third pair.
00:28
Now the probability of their offspring with particular genotypes can be determined individually using punez square.
00:38
So, for the first pair of gene, that is for earlobes, heterozygous and homozygous recessive are crossed.
00:59
The genotypes will be heterozygous, homozygous recessive, again heterozygous and homozygous recessive.
01:08
Now for the second gene pair, which is for widow peak or straight line, so the mother possess homozygous recessive and the father is heterozygous.
01:26
The genotypes here will be heterozygous, again heterozygous, then homozygous recessive, again homozygous recessive.
01:37
Now for the third gene pair, which is for tongue rolling, the ability to roll the tongue which is dominant and the inability is recessive.
01:52
So both the pairs are heterozygous.
01:56
The genotype here will be homozygous dominant, heterozygous, again heterozygous, homozygous recess.
02:05
Now the proportion of heterozygous for the first pair will be 1 by 2 whereas homozygous recessive will be also 1 by 2...