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h = 24cm l = \sqrt{h^2 + (r_1 - r_2)^2} = \sqrt{24^2 + 10^2} = 26cm Curved surface area of bucket = \pi (r_1 + r_2)l = \frac{22}{7} \times (15 + 5) \times 26 = \frac{22 \times 20 \times 26}{7} = \frac{11440}{7} cm^2 or 1634.2cm^2 Sec\theta + tan\theta = p \frac{1}{cos\theta} + \frac{sin\theta}{cos\theta} = p 1 + sin\theta = pcos\theta = p\sqrt{1 - sin^2\theta} (1 + sin\theta)^2 = p^2(1 - sin^2\theta) 1 + sin^2\theta + 2sin\theta = p^2 - p^2sin^2\theta (1 + p^2)sin^2\theta + 2sin\theta + (1 - p^2) = 0 D = 4 - 4(1 + p^2)(1 - p^2) Sin\theta = \frac{-2 \pm \sqrt{4p^4}}{2(1 + p^2)} = \frac{-1 \pm p^2}{(1 + p^2)} = \frac{p^2 - 1}{p^2 + 1}, -1 :: Cosec \theta = \frac{p^2 + 1}{p^2 - 1}, -1

          h = 24cm
l = \sqrt{h^2 + (r_1 - r_2)^2}
= \sqrt{24^2 + 10^2} = 26cm
Curved surface area of bucket = \pi (r_1 + r_2)l
= \frac{22}{7} \times (15 + 5) \times 26
= \frac{22 \times 20 \times 26}{7}
= \frac{11440}{7} cm^2 or 1634.2cm^2
Sec\theta + tan\theta = p
\frac{1}{cos\theta} + \frac{sin\theta}{cos\theta} = p
1 + sin\theta = pcos\theta
= p\sqrt{1 - sin^2\theta}
(1 + sin\theta)^2 = p^2(1 - sin^2\theta)
1 + sin^2\theta + 2sin\theta = p^2 - p^2sin^2\theta
(1 + p^2)sin^2\theta + 2sin\theta + (1 - p^2) = 0
D = 4 - 4(1 + p^2)(1 - p^2)
Sin\theta = \frac{-2 \pm \sqrt{4p^4}}{2(1 + p^2)} = \frac{-1 \pm p^2}{(1 + p^2)}
= \frac{p^2 - 1}{p^2 + 1}, -1
:: Cosec \theta = \frac{p^2 + 1}{p^2 - 1}, -1

h = 24cm
l = √(h^2 + (r1 - r2)^2)
= √(24^2 + 10^2) = 26cm
Curved surface area of bucket = π(r1 + r2)l
= (22)/(7) ×(15 + 5) ×26
= (22 ×20 ×26)/(7)
= (11440)/(7) cm^2 or 1634.2cm^2
Secθ+ tanθ= p
(1)/(cosθ) + (sinθ)/(cosθ) = p
1 + sinθ= pcosθ= p√(1 - sin^2θ)
(1 + sinθ)^2 = p^2(1 - sin^2θ)
1 + sin^2θ+ 2sinθ= p^2 - p^2sin^2θ(1 + p^2)sin^2θ+ 2sinθ+ (1 - p^2) = 0
D = 4 - 4(1 + p^2)(1 - p^2)
Sinθ= (-2 ±√(4p^4))/(2(1 + p^2)) = (-1 ±p^2)/((1 + p^2))
= (p^2 - 1)/(p^2 + 1), -1
:: Cosec θ= (p^2 + 1)/(p^2 - 1), -1

Added by Marissa C.

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