We can use the trigonometric identity $\sin 2x = 2 \sin x \cos x$ to rewrite the integrand as:
$$\int \frac{1}{2} \sin 2x \, dx$$
Now we can use the substitution $u = 2x$, $du = 2 dx$ to get:
$$\frac{1}{2} \int \sin u \, \frac{du}{2} = -\frac{1}{4} \cos u +
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