Calculate √(23)79 1, and express it in the form b√9 where 0 < b < 79. What is b?
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In other words, we need to find 23^79 mod 79. Using Euler's theorem, we know that a^(phi(n)) ≡ 1 (mod n) for any integer a and n that are relatively prime. In this case, a = 23 and n = 79, and since they are relatively prime, we can apply Euler's theorem. The Show more…
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