(c) Evaluate $\oint_C \frac{\sin^6 z}{(z-\frac{\pi}{2})^2} dz$ where C is the circle $|z| = 1$.
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The differential dz can be expressed as dz = i(re^(iθ))dθ, since dz/dθ = ire^(iθ) by differentiating z = re^(iθ) with respect to θ. Substituting this into the integral, we have ∫ dz = ∫ i(re^(iθ))dθ. Now, we need to determine the limits of integration for θ. Show more…
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