(b) $P(X > 0.6, Y > 2.8) = $\Box$ (Simplify your answer.)
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6. From the given information, we know that X follows a uniform distribution on the interval [0,1]. Therefore, the probability that X is greater than 0.6 is: P(X > 0.6) = 1 - P(X ≤ 0.6) = 1 - 0.6 = 0.4 Show more…
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