b) lim 1-sinx x-"1z cos x
Added by John M.
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It is given as: lim (1 - sinx) / (x - pi/2) * cosx as x -> pi/2 Now, we can use L'Hopital's Rule since the limit is in the indeterminate form 0/0 as x approaches pi/2. To apply L'Hopital's Rule, we need to differentiate both the numerator and the denominator Show more…
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