b) Find $\sum_{k=1}^{20} k(2k^2 - 1)(k + 4) =?$
Added by -Ngel L.
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Step 1
First, we can set each factor equal to zero and solve for k: 2k^2 - k = 0 k(2k - 1) = 0 k = 0 or 2k - 1 = 0 k = 0 or 2k = 1 k = 0 or k = 1/2 Show more…
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