\( (b) \int \frac{x^2 - 2x - 1}{(x - 1)^2 (x^2 + 1)} dx \)
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Step 1
First, we need to find the inverse function of f(x). Let's assume that f(x) = 2x - 1. To find the inverse function, we need to switch x and y and solve for y: x = 2y - 1 x + 1 = 2y y = (x + 1)/2 Therefore, f^-1(x) = (x + 1)/2. Show more…
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