A small, battery-powered, electric motorboat that can travel at a speed of 2.95 m/s in still water is operating in a river with a flow speed of 1.30 m/s. For each of the following two cases, determine the requested information for a river that is 246 m wide. (a) Case 1: when the boat is pointed straight across the river, determine the speed $v_{bl}$ of the boat as viewed by someone on land, the distance $d$ the boat is swept downstream before reaching the other side, and the time $t_1$ it takes the boat to make the crossing. $v_{bl} = \boxed{\text{ }\text{ }}\text{ m/s}$ $d = \boxed{\text{ }\text{ }}\text{ m}$ $t_1 = \boxed{\text{ }\text{ }}\text{ s}$ (b) Case 2: if the boat operator wants to land the boat straight across the river from the launch site, determine the speed $v_{bl}$ of the boat as viewed by someone on land, the angle $\beta$ upstream at which the boat should be pointed, and the time $t_2$ it takes the boat to make the crossing. $v_{bl} = \boxed{\text{ }\text{ }}\text{ m/s}$ $\beta = \boxed{\text{ }\text{ }}^\circ$ $t_2 = \boxed{\text{ }\text{ }}\text{ s}$
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However, in this case, we are given the speed and need to find the time. Let's assume the distance of the crossing is d meters. We are given the speed of the crossing as m/s. Let's call this speed v. The formula to calculate time is: Time = Distance / Show more…
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