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24. Find $\frac{dy}{dx}$ and find the slope at $\theta = -\frac{\pi}{3}$ \\ $x = 2 + 2\sec\theta$, $y = 1 + 2\tan\theta$ 

          24. Find $\frac{dy}{dx}$ and find the slope at $\theta = -\frac{\pi}{3}$ \\
$x = 2 + 2\sec\theta$, $y = 1 + 2\tan\theta$
24. Find (dy)/(dx) and find the slope at θ = -(π)/(3) x = 2 + 2secθ, y = 1 + 2tanθ

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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aFind/nd find the slope at = =2+recy1+2uan0
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Transcript

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00:01 This is sort of a fun problem.
00:03 And the whole theme is that if you could rewrite this problem in the form y equals mx plus b, then whatever number is being multiplied by m would represent the slope.
00:16 So as we look at this problem where we have 2y plus 3 is equal to 0, you might notice that there's not even a x value in the problem.
00:28 But sometimes what i'll tell students to do is just go ahead and put in a zero times x because zero times anything is still zero.
00:36 So now when i go to solve this, what i would do is just subtract the three to the right side and then to solve for why, you could just divide everything by two...
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