(a) (3 marks) Show that if \overrightarrow{r}(t) is a smooth vector function with $||\overrightarrow{r}(t)|| = 1$, then \frac{d}{dt}\overrightarrow{r}(t) \cdot \overrightarrow{r}(t) = 0.
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A smooth vector field on a manifold M is a smooth assignment of a tangent vector to each point on M. In other words, it is a function that assigns a tangent vector to each point on the manifold in a smooth way. Now, let's consider two smooth vector fields X and Y Show more…
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