Question

A certain capacitor has rectangular plates $59 \mathrm{cm}$ by $33 \mathrm{cm}$, and the gap width is $0.27 \mathrm{mm}$. If the gap is filled with a material whose dielectric constant is $2.9,$ what is the capacitance of this capacitor?

          A certain capacitor has rectangular plates $59 \mathrm{cm}$ by $33 \mathrm{cm}$,
and the gap width is $0.27 \mathrm{mm}$. If the gap is filled with a material whose dielectric constant is $2.9,$ what is the capacitance of this capacitor?

Added by Dustin S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

Step 1

First, we need to find the area of the plates. The area of a rectangle is given by the formula $A = length \times width$. In this case, the length is $59 \mathrm{cm}$ and the width is $33 \mathrm{cm}$. So, the area of the plates is: $A = 59 \mathrm{cm} \times 33 Show more…

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A certain capacitor has rectangular plates $59 \mathrm{cm}$ by $33 \mathrm{cm}$, and the gap width is $0.27 \mathrm{mm}$. If the gap is filled with a material whose dielectric constant is $2.9,$ what is the capacitance of this capacitor?