Question

(a) \frac{(2n)!}{(n!)^2} is an even integer.

Name: (a) ((2n)!)/((n!)^2) is an even integer.
Uploaded: 2021-09-16T14:34:03-08:00
Duration: 2 min 12 s
Channel: Aman Gupta
Description: (a) ((2n)!)/((n!)^2) is an even integer.

          (a) \frac{(2n)!}{(n!)^2} is an even integer.

Added by Sarah S.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Aman Gupta

09/16/2021

Step 1

Then $$E = \frac{(2n)!}{(n!)^2}$$ For $n=1$, $E = \frac{2!}{1^2} = 2$, which is an even integer. For $n=2$, $E = \frac{4!}{(2!)^2} = \frac{24}{4} = 6$, which is an even integer. For $n=3$, $E = \frac{6!}{(3!)^2} = \frac{720}{36} = 20$, which is an even integer. Show more…

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