E = ((a^3b)^-3 ×(ab^3)^3 ×(a^-2b^2)^3)/((ab^-1)^-2 ×(a^-1b^2)^3 ×b^-4)

Name: E = ((a^3b)^-3 ×(ab^3)^3 ×(a^-2b^2)^3)/((ab^-1)^-2 ×(a^-1b^2)^3 ×b^-4)
Uploaded: 2023-07-22T00:10:34-08:00
Duration: 1 min 3 s
Channel: Numerade
Description: E = ((a^3b)^-3 ×(ab^3)^3 ×(a^-2b^2)^3)/((ab^-1)^-2 ×(a^-1b^2)^3 ×b^-4)

Question

Pammi Eswari · Answer

Here we have to find out the factors of given expression. For that first we will rearrange the t

Pammi Eswari · Answer

Here we have to find out the factors of given expression. For that, first we will rearrange the

Anas Venkitta · Answer

So in the given question we are told that the terms the numbers A, B and C are in a Gp. And now

William F · Answer

Alright, so A, B is 2 .5, so this is 2 .5. B, C, is 4 and 2 thirds. So that&#x27;s 4 and 2 thirds. C

Saurabh Chandra · Answer

So in this question we have to find the limiting value of this expression when x is approaching

Question

E = \frac{(a^3b)^{-3} \times (ab^3)^3 \times (a^{-2}b^2)^3}{(ab^{-1})^{-2} \times (a^{-1}b^2)^3 \times b^{-4}}

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