1. A) 52x^5 + (7x^2)/(x^5) - 7e^4x B) ∫((x+3))/((x^2+6x)^2) dx

Name: 1. A) 52x^5 + (7x^2)/(x^5) - 7e^4x B) ∫((x+3))/((x^2+6x)^2) dx
Uploaded: 2023-06-12T14:20:20-08:00
Duration: 1 min 8 s
Channel: Numerade
Description: 1. A) 52x^5 + (7x^2)/(x^5) - 7e^4x B) ∫((x+3))/((x^2+6x)^2) dx

Question

Suman Saurav Thakur · Answer

Hello, I have a question in this I need to evaluate 0 to 2, 3 minus x squared dx. So this will b

Adi S · Answer

The given differential equation dx over dt is equal to 7 e to the power of t negative 5 with ini

Sri K · Answer

Let&#x27;s discuss this question. So here we need to find the correct answer for this question. So he

Madhur L · Answer

Hello students, given that t x square minus x into dt plus 3 x square plus t into dx equals to 0

Madhur L · Answer

Hello students, in this problem we are going to solve the integration 1 by 50 integral x divided

Question

1. A) $52x^5 + \frac{7x^2}{x^5} - 7e^4x$ \newline B) $\int \frac{(x+3)}{(x^2+6x)^2} dx$

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