a) 4 \cos x - 3 = 0 b) 2\sin^2 x - 3\sin x + 1 = 0
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4cos X - 3 = 0 4cos X = 3 cos X = \frac{3}{4} b) Now, let's solve for sin x in the equation 2sin^2 x - 3sin x + 1 = 0. This is a quadratic equation in terms of sin x. Let's use the quadratic formula to solve for sin x: sin x = \frac{-b \pm \sqrt{b^2 - Show more…
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