9 over y + 2 over 5 + 3 over 5y
Added by Donna C.
Step 1
The smallest common multiple of y, 5, and 5y is 5y. So, we need to rewrite each fraction with a denominator of 5y: 9/y = (9/1) * (5y/y) = 45y/5y 2/5 = (2/5) * (y/y) = 2y/5y 3/5y = (3/5y) * (5/5) = 15/5y Show more…
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