8.29 In Haskell syntax: fg x = g (g x). What polymorphic type does this function have?
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The type of `g` is not specified, so it can be any type. The type of `x` is also not specified, so it can be any type. The type of `g x` is determined by the type of `g` and `x`. Since `g` is applied to `x`, the type of `x` must be the same as the type of Show more…
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