\int_{0}^{\ln 2} \int_{0}^{\ln 5} e^{2x - y} dx dy
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Step 1: Write the integral and factor the integrand: I = ∫_{y=0}^{ln 2} ∫_{x=0}^{ln 5} e^(2x - y) dx dy = ∫_{0}^{ln 2} ∫_{0}^{ln 5} e^(2x) e^(-y) dx dy. Show more…
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