∑k=6^∞(2)/(k-5). ∑k=1^∞(1)/(1+k^2).

Name: ∑k=6^∞(2)/(k-5). ∑k=1^∞(1)/(1+k^2).
Uploaded: 2023-04-12T05:13:55-08:00
Duration: 1 min 16 s
Channel: Numerade
Description: ∑k=6^∞(2)/(k-5). ∑k=1^∞(1)/(1+k^2).

Question

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Question

$\sum_{k=6}^{\infty} \frac{2}{k-5}$. \newline $\sum_{k=1}^{\infty} \frac{1}{1+k^2}$.

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