5. (1 + 2x2)y" + Txy' + 2y = 0
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We assume that the solution has the form y = e^(mx), where m is a constant to be determined. Then, we substitute this into the differential equation and obtain: (1 + 2x^2)(m^2 e^(mx)) + Tx (m e^(mx)) + 2e^(mx) = 0 Simplifying this expression, we get: (m^2 + Show more…
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