00:03
This is the answer to chapter one, problem number 29, from the smith organic chemistry textbook.
00:12
And this problem asks us to identify the hybridization around the indicated atoms in each of these three molecules.
00:26
And so sort of an easy way to do that is related to the way that we were identifying.
00:34
Geometry around particular atoms earlier in this chapter.
00:38
So we can count the groups around each atom and then correlate that with a particular orbital hybridization.
00:49
And so in a, this first carbon has four groups around it.
00:55
So it has three hydrogens and then another carbon.
00:59
And so four groups is going to be sp3.
01:03
So it's tetrachy.
01:04
When we have tetrahedral geometry, we have sp3 orbitals.
01:11
And then looking at the other carbon that we're asked about in a, it has two groups around it, a carbon and a hydrogen.
01:22
Also, as i've said before, any molecule that's part of a triple bond, or any atom that's part of a triple bond in a molecule is going to have linear geometry.
01:31
So it's also true that it's going to have sp hybridization.
01:37
And so this carbon does have linear geometry, and it has sp hybridization.
01:43
And so we'll follow this strategy for the other two molecules and this problem.
01:48
So in b, the carbon that we're asked about has three groups around it.
01:55
So it's going to have trigonal planar geometry, and so it's going to be sp2 hybridized.
02:03
Something that you, it would be good to learn though that you may want to know is when a carbon is making a double bond to something, it's sp2 hybridized.
02:13
And so anytime that you see a carbon with a double bond, it's going to be sp2 as it is here...