4. (12 points) Solve $y^{(6)} - 3y^{(4)} + 3y'' - y = 0$
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First, we need to find the characteristic equation by assuming y=e^(rt): r^2 + 3r + 3 = 0 Using the quadratic formula, we get: r = (-3 ± sqrt(3^2 - 4(1)(3)))/2(1) r = (-3 ± i√3)/2 So the general solution is: y(t) = c1e^(-3t/2)cos((√3/2)t) + Show more…
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