Evaluate the indefinite integral, ∫2x(x^2 + 1)^6 dx.
Added by Russell A.
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Step 1
First, we can simplify the integrand by expanding the polynomial: 2x(x^2 + 1)^6 = 2x(x^12 + 6x^10 + 15x^8 + 20x^6 + 15x^4 + 6x^2 + 1) Show more…
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