3) (7.2) Use the Laplace transform to solve the initial-value problem. $y'' + y = 3$; $y(0) = 1$, $y'(0) = 1$
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The Laplace transform of y'' is s^2Y(s) - sy(0) - y'(0), where Y(s) is the Laplace transform of y(t). So, taking the Laplace transform of the equation y'' + y = 3 yields: s^2Y(s) - sy(0) - y'(0) + Y(s) = 3 Show more…
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