3.4.2v - 34' + %y = 0. v(0) = 3v(0) =
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v(0) = (34 ± sqrt(34^2 - 4y))/2 3v(0) = 3(34 ± sqrt(34^2 - 4y))/2 Simplifying, we get: v(0) = 17 ± sqrt(17^2 - y) 3v(0) = 51 ± 3sqrt(17^2 - y) Since v(0) = 3v(0), we have: 17 ± sqrt(17^2 - y) = 51 ± 3sqrt(17^2 - y) Solving for y, we get: y = 17^2 Show more…
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