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In problems 3 through 10, we're going to be calculating dot products.
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So first, we're going to have negative 2, 1 3rd, and negative 512.
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So we have negative 2 times negative 5, which gives us 10, plus 1 3rd times 12 gives us 4.
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So we end up getting 14 as our answer.
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And for the next one, we have negative 2 times 0 .7, so that's a negative 1 .4, plus 3 times 1 .2.
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That's positive 1 .6.
00:28
So we get a point 2 as our dot product.
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Then we have 4 times 6, which is 24.
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1 times negative 3 is negative 3.
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And then we have 1 4th times a negative 8.
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That's a negative 2.
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So we end up getting 19 as our dot product.
00:48
For problem 6, we're going to have s times t, which is st...