3. If $3x^2 - 2x + 7 = 0$, then $(x - \frac{1}{3})^2 = $
Added by Robert S.
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Step 1
Substituting these values, we get: x = (-2 ± √(2^2 - 4(3)(7))) / 2(3) x = (-2 ± √(-52)) / 6 Since the square root of a negative number is not a real number, this equation has no real solutions. Show more…
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