3). 25y^2 + 20y + 4 = 0, y(5) = 4e-2, y(5) = e*
Added by Cesar P.
Step 1
First, we need to find the general solution to the differential equation 25y" + 20y' + 4 = 0. We can start by assuming a solution of the form y = e^(rt), where r is a constant. Then, we can substitute this into the differential equation and solve for r: 25r^2 Show more…
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