Given rational function $r(x) = \frac{(2x^2 - 2)(x + 3)}{(x^2 - 6x + 8)(x + 3)}$
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Using the distributive property, we can expand it as: 2x2(x) + 2x2(3) - 2(x) - 2(3) Simplifying further, we get: 2x3 + 6x2 - 2x - 6 Now, we can substitute this expression for rfx) in the given rational function: rfx) = (x2 6x + 8)(x + 3) rfx) = (x - 2)(x - Show more…
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