Question

2. Compute $\int_9^{16} \frac{\sqrt{x}}{x - 4} dx$ by doing a u-sub and then writing $u^2 = u^2 - 4 + 4$.

          2. Compute $\int_9^{16} \frac{\sqrt{x}}{x - 4} dx$ by doing a u-sub and then writing $u^2 = u^2 - 4 + 4$.
        
2. Compute ∫9^16(√(x))/(x - 4) dx by doing a u-sub and then writing u^2 = u^2 - 4 + 4.

Added by Claudia T.

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Calculus: Early Transcendentals
Calculus: Early Transcendentals
James Stewart 8th Edition
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Compute by doing a u-sub and then writing u = u - 4 + 4.
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Transcript

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00:01 We need to simplify the following expression.
00:03 In order to do that, we have to have a common denominator.
00:06 So our four has a one as our denominator.
00:10 So our common denominator is going to be u times u plus five.
00:16 So for our first term, we need to multiply by u and u plus five.
00:22 Our second term, we need to multiply just by u plus five.
00:26 And our last term, we need to just multiply by u.
00:29 So when we rewrite this, this is 4 times u times u plus 5 plus 2 times u plus 5 minus 3 u times you times you.
00:43 And that's all over the common denominator of u times u times you plus 5...
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