(x^2 + 3)/((x - 2)(x - 1)(x - 3)) = (A)/((x - 2)) + (B)/((x - 1)) + (C)/((x - 3))

Name: (x^2 + 3)/((x - 2)(x - 1)(x - 3)) = (A)/((x - 2)) + (B)/((x - 1)) + (C)/((x - 3))
Uploaded: 2023-07-20T15:12:31-08:00
Duration: 21 s
Channel: Numerade
Description: (x^2 + 3)/((x - 2)(x - 1)(x - 3)) = (A)/((x - 2)) + (B)/((x - 1)) + (C)/((x - 3))

Question

Anthony Ramos · Answer

Okay, so now we have this vector in the complex space and we need to first found the conjugate,

John Nicolle · Answer

So first of all in this first part we need to plot a graph so we have x is equals to minus 6 and

Luke Schroeder · Answer

Okay, what we&#x27;re looking at here is, well, if you just look at it and you understand it&#x27;s parent

Christopher Stanley · Answer

Here we want to multiply 6 plus 7i times 6 minus 7i. Now 6 times 6 is 36. 6 times negative 7 is

Alison Rodriguez · Answer

When you&#x27;re combining like terms or adding your subtracting complex numbers, always take a look

Question

\frac{x^2 + 3}{(x - 2)(x - 1)(x - 3)} = \frac{A}{(x - 2)} + \frac{B}{(x - 1)} + \frac{C}{(x - 3)}

Please give Ace some feedback