2. $y(x^2 - y^2)dx - x(x^2 + y^2)dy = 0$.
Added by Scott P.
Close
Step 1
First, we need to check if the given differential equation is exact or not. To do this, we need to check if the partial derivative of the coefficient of dx with respect to y is equal to the partial derivative of the coefficient of dy with respect to x. In this Show more…
Show all steps
Your feedback will help us improve your experience
Oluwadamilola Ameobi and 91 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
2. (x2 +y2)dx+(x2 −xy)dy = 0
Israel H.
dy/dx = 1/(2sqrt{x}) + 8, y(1) = 3
Adi S.
Madhur L.
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Watch the video solution with this free unlock.
EMAIL
PASSWORD