2. Solve: $(y^2 + 1)dx = y \sec^2 x \, dy$
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Step 1
First, we need to rearrange the equation to separate the variables: (y^2 + 1)dx = y sec(x)dy Divide both sides by y sec(x): (y^2 + 1)/(y sec(x)) dx = dy Now we can integrate both sides: ∫(y^2 + 1)/(y sec(x)) dx = ∫dy Using the trigonometric identity sec^2(x) Show more…
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