2. $f(x) = \cos^3(x) - \sin^3(x)$ on $[0,4]$
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Step 1
First, we need to determine the critical points of the function f(x) on the interval [0,4]. To do this, we take the derivative of f(x) and set it equal to zero: f'(x) = -sin(x)sin(x) + cos(x)cos(x) f'(x) = cos^2(x) - sin^2(x) f'(x) = cos(2x) Setting f'(x) = 0, Show more…
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