(2) Calculate \phi(10!). (You should show your work.)
Added by Donald W.
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10! = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 3628800 Now, we need to find the number of trailing zeros in 10!. Trailing zeros are formed by the product of 2 and 5. So, we need to find the number of pairs of 2 and 5 in the prime factorization of 10!. Let's Show more…
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