√(289^2x^2 - 8x - 1) = 17^x^2 - 3x + 5

Name: √(289^2x^2 - 8x - 1) = 17^x^2 - 3x + 5
Uploaded: 2023-07-20T11:59:09-08:00
Duration: 21 s
Channel: Numerade
Description: √(289^2x^2 - 8x - 1) = 17^x^2 - 3x + 5

Question

Andrew Noble · Answer

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Aman Gupta · Answer

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Aman Gupta · Answer

In this problem, we first need to note that for the square root to be defined, 17 plus x should

Cheryl Glor · Answer

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Sonam Khatri · Answer

In this problem, we have to find the solution of the given equation 2x2x2 plus 8x minus 25 is eq

Question

\sqrt{289^{2x^2 - 8x - 1}} = 17^{x^2 - 3x + 5}

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