2. [6 points] Compute all the eigenvalues and eigenvectors of A (2a) -
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Let's start with λ1: (2a - 1 - λ1)x + 2y = 0 x + (2a - λ1)y = 0 Substituting λ1 and simplifying, we get: (2a - 1 - 2a - 1 - √[4a^2 - 4a + 9])x + 2y = 0 x + (2a - 2a - 1 - √[4a^2 - 4a + 9])y = 0 Simplifying further, we get: -√[4a^2 - 4a + 9]x + 2y = 0 x - Show more…
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