2. \mathcal{L}\{(2t-2)\mathcal{U}(t-2)\} \mathcal{L}\{(3t-3)\mathcal{U}(t-3)\}
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The convolution of two functions is defined as: €(f*g)(t) = ∫f(τ)g(t-τ)dτ In our case, f(τ) = (2τ-2)u(τ_2) and g(t-τ) = (3(t-τ)-3)u(t-τ-3). So, we need to find the convolution of these two functions: €(f*g)(t) = ∫(2τ-2)u(τ_2) * (3(t-τ)-3)u(t-τ-3)dτ Now, we Show more…
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