2 2i(i - 1)+ (v3 -i)3 + (1+i)1 -i)
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Step 1
First, we need to simplify the expression inside the parentheses: 2i(i - 1) = 2i^2 - 2i = -2i - 2i^2 (since i^2 = -1) (v3 - i)^3 = (v3)^3 - 3(v3)^2i + 3v3(i^2) - i^3 = 27 - 9v3i - 3i + i = 28 - 9v3i (1+i)1 -i = 1 + i - i - 1 = 0 Show more…
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