h(x) = ((x - 1)(x + 5))/(x^2 - 4) vertical asymptotes(s)

Name: h(x) = ((x - 1)(x + 5))/(x^2 - 4) vertical asymptotes(s)
Uploaded: 2023-07-19T08:06:32-08:00
Duration: 15 s
Channel: Numerade
Description: h(x) = ((x - 1)(x + 5))/(x^2 - 4) vertical asymptotes(s)

Question

Ankit Gupta · Answer

have h of x is equal to x square minus 4 divided by x multiplied by x plus 5 multiplied by x min

Kathleen Carty · Answer

I want to find vertical asymptotes. So you will have vertical asymptopes where the denominator e

Carson Merrill · Answer

To find the vertical asymptote, we let the denominator equals zero, and we find that x equals ne

Yujie Wang · Answer

Okay, so for the vertical n -sumtote is x equals to minus 6, okay, which makes the denominator e

Carson Merrill · Answer

Here we are first trying to find the vertical asymptote. So we are going to let our denominator

Question

$h(x) = \frac{(x - 1)(x + 5)}{x^2 - 4}$ vertical asymptotes(s)

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