(b) $\int_0^{1/\sqrt{3}} 2 \cdot \frac{t^2 - 1}{t^4 - 1} dt$
Added by Heather A.
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We can do this by finding a common denominator and combining the terms: 1/v3 t^2 + 1 = (1 + v3 t^2)/v3 t^2 Show more…
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