18. $f(x, y) = (x^2 + y^2)e^{-x}$
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To do this, we treat y as a constant and differentiate f with respect to x: ∂f/∂x = 2xe-x + (x2 + y2)(-e-x) Simplifying this expression, we get: ∂f/∂x = (2x - x2 - y2)e-x Show more…
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