Question

Find the exact value of $\cos\frac{\pi}{16}\cos\frac{3\pi}{16} - \sin\frac{\pi}{16}\sin\frac{3\pi}{16}$. $\circ -\frac{\sqrt{2}}{2}$ $\circ -\frac{\sqrt{3}}{2}$ $\circ \frac{\sqrt{2}}{2}$ $\circ \frac{\sqrt{3}}{2}$

          Find the exact value of $\cos\frac{\pi}{16}\cos\frac{3\pi}{16} - \sin\frac{\pi}{16}\sin\frac{3\pi}{16}$.

$\circ -\frac{\sqrt{2}}{2}$

$\circ -\frac{\sqrt{3}}{2}$

$\circ \frac{\sqrt{2}}{2}$

$\circ \frac{\sqrt{3}}{2}$

Find the exact value of cos(π)/(16)cos(3π)/(16) - sin(π)/(16)sin(3π)/(16).

∘ -(√(2))/(2)

∘ -(√(3))/(2)

∘(√(2))/(2)

∘(√(3))/(2)

Added by Ramon B.

Introductory and Intermediate Algebra for College Students 4th

Robert Blitzer 4th Edition

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Solved by Expert Darshan Maheshwari

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Step 1: The given sequence is "16 0 v2 2 V3 2 V2 2 V3 2". Show more…

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16 0 v2 2 V3 2 V2 2 V3 2

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Question

Find the exact value of $\cos\frac{\pi}{16}\cos\frac{3\pi}{16} - \sin\frac{\pi}{16}\sin\frac{3\pi}{16}$. $\circ -\frac{\sqrt{2}}{2}$ $\circ -\frac{\sqrt{3}}{2}$ $\circ \frac{\sqrt{2}}{2}$ $\circ \frac{\sqrt{3}}{2}$

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