Divide (a+1)(a+1)(a+3) by a(a+3)
Added by Jonathan R.
Step 1
First, we need to use the distributive property to expand the numerator of the fraction: (a+1)(a+1)(a+3) = (a+1)(a^2+4a+3) = a(a^2+4a+3) + 1(a^2+4a+3) = a^3 + 4a^2 + 3a + a^2 + 4a + 3 = a^3 + 5a^2 + 7a + 3 Now we can divide this expression by a(a+3) using long Show more…
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