\frac{1+2a}{1+2a+4a^2} - \frac{2a}{2a-1} - \frac{8a^3}{1-8a^3}
Added by Kim B.
Close
Step 1
1 + 20 = 21 2a(2a - 1) = 4a^2 - 2a 8a^3 - 1 - 8a^3 = -1 1 + 20 + 402 = 423 So the final expression is: 21 + 4a^2 - 2a - 1 + 423 Show more…
Show all steps
Your feedback will help us improve your experience
Cheryl Glor and 97 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
[(a^2 + 7a + 12) / (a - 2)] / [(a^2 + 9a + 18) / (a^2 - 7a +10)]
Bradley D.
1. 8 + 20 + 32 + 44 + ... ; n = 10 2. sum_{n=0}^{20} 3(frac{3}{2})^n 3. 8 + 6 + frac{9}{2} + frac{27}{8} + ... 4. sum_{n=1}^{9} 2^{n-1}
Piyush Kumar G.
$$ 20 a^{3}+37 a^{2}+8 a $$
Factoring Polynimials
Factoring Trinomials of the Form $a x^{2}+b x+c$ by Grouping
Recommended Textbooks
Elementary and Intermediate Algebra
Algebra and Trigonometry
Watch the video solution with this free unlock.
EMAIL
PASSWORD